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Erdős Problem 160

Reference: erdosproblems.com/160

namespace Erdos160

Let $h(n)$ be the smallest $k$ such that ${1,\ldots,n}$ can be coloured with $k$ colours so that every four-term arithmetic progression must contain at least three distinct colours.

noncomputable def erdos_160.h (n : ) : := sInf {k | (colouring : Finset.Icc 1 n Fin k), (progression : Set ), (progression Finset.Icc 1 n progression.IsAPOfLength 4) 3 (colouring '' {k | (k : ) progression}).ncard} open Filter

On Mathoverflow user leechlattice shows that $h(n) \ll n^{\frac 2 3}$.

@[category research solved, AMS 5 51] theorem declaration uses 'sorry'erdos_160.known_upper : (fun n => (erdos_160.h n : )) =O[atTop] fun n => (n : ) ^ ((2 : ) / 3) := (fun n => (h n)) =O[atTop] fun n => n ^ (2 / 3) All goals completed! 🐙 open Real

Estimate $h(n)$ by finding a better upper bound.

@[category research open, AMS 5 51] theorem declaration uses 'sorry'erdos_160.better_upper : let upper_bound : := answer(sorry) (fun n => (erdos_160.h n : )) =O[atTop] upper_bound upper_bound =o[atTop] fun n => (n : ) ^ ((2 : ) / 3) := let upper_bound := sorry; (fun n => (h n)) =O[atTop] upper_bound upper_bound =o[atTop] fun n => n ^ (2 / 3) All goals completed! 🐙

Estimate $h(n)$ by finding a better lower bound.

@[category research open, AMS 5 51] theorem declaration uses 'sorry'erdos_160.better_lower: let lower_bound : := answer(sorry) (lower_bound =O[atTop] fun n => (erdos_160.h n : )) c > 0, (fun (n : ) => exp (c * log n ^ ((1 : ) / 12))) =O[atTop] (fun n => (erdos_160.h n : )) c > 0, (fun (n : ) => exp (c * log n ^ ((1 : ) / 12))) =o[atTop] lower_bound := let lower_bound := sorry; (lower_bound =O[atTop] fun n => (h n)) c > 0, ((fun n => rexp (c * log n ^ (1 / 12))) =O[atTop] fun n => (h n)) c > 0, (fun n => rexp (c * log n ^ (1 / 12))) =o[atTop] lower_bound All goals completed! 🐙

The observation of Zachary Hunter in that question coupled with the bounds of Kelley-Meka KeMe23 imply that $$h(N) \gg \exp(c(\log N)^{\frac 1 {12}})$$ for some $c > 0$.

@[category research solved, AMS 5 51] theorem declaration uses 'sorry'erdos_160.variants.known_lower : c > 0, (fun (n : ) => exp (c * log (n : ) ^ ((1 : ) / 12))) =O[atTop] fun n => (erdos_160.h n : ):= c > 0, (fun n => rexp (c * log n ^ (1 / 12))) =O[atTop] fun n => (h n) All goals completed! 🐙 end Erdos160