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Erdős Problem 203

Reference: erdosproblems.com/203

namespace Erdos203

Is there an integer $m$ with $(m, 6) = 1$ such that none of $2^k \cdot 3^\ell \cdot m + 1$ are prime, for any $k, \ell \ge 0$?

@[category research open, AMS 5] theorem declaration uses 'sorry'erdos_203 : answer(sorry) m, m.Coprime 6 k l, ¬ (2^k * 3^l * m + 1).Prime := True m, m.Coprime 6 (k l : ), ¬Nat.Prime (2 ^ k * 3 ^ l * m + 1) All goals completed! 🐙 -- TODO(rdivyanshu): add statements about covering system and odd integers `m` such that none of 2^k*m + 1 is prime end Erdos203