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Erdős Problem 469

Reference: erdosproblems.com/469

namespace Erdos469

The proposition that n is a sum of distinct proper divisors.

def Nat.IsSumDivisors (n : ) : Prop := S n.properDivisors, d S, d = n open Erdos469

Let $A$ be the set of all $n$ such that $n = d_1 + ⋯ + d_k$ with $d_i$ distinct proper divisors of $n$, but this is not true for any $m ∣ n$ with $m < n$. Does: $$ \sum_{n ∈ A} \frac 1 n $$ converge?

@[category research open, AMS 11] theorem declaration uses 'sorry'erdos_469 : letI A := {n : | 0 < n n.IsSumDivisors m < n, m n ¬ m.IsSumDivisors} answer(sorry) Summable fun n : A 1 / (n : ) := True Summable fun n => 1 / n All goals completed! 🐙 end Erdos469