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Erdős Problem 593

References:

    erdosproblems.com/593

    [EGH75] Erdős, Paul and Galvin, Fred and Hajnal, András, On set-systems having large chromatic number and not containing prescribed subsystems. Infinite and finite sets (Colloq., Keszthely, 1973; dedicated to P. Erdős on his 60th birthday), Vol. I. Colloq. Math. Soc. János Bolyai 10, North-Holland (1975), 425–513.

    [Er95d] Erdős, Paul, Some of my favourite problems in various branches of combinatorics. Matematiche (Catania) 47 (1992), no. 2, 231–240 (1995).

open Cardinal Set SimpleGraph namespace Erdos593

Erdős Problem 593 ($500): Characterize those finite 3-uniform hypergraphs which appear in every 3-uniform hypergraph of chromatic number $> \aleph_0$.

A natural conjectural characterization, recorded here, is that the obligatory finite 3-uniform hypergraphs are exactly the 2-colorable ones (Property B). The forward direction (IsObligatory → IsTwoColorable) and converse (IsTwoColorable → IsObligatory) are stated as separate variants below; in the graph case ($r = 2$), Erdős–Galvin–Hajnal [EGH75] proved the analogous result (obligatory ⇔ bipartite).

@[category research open, AMS 5] theorem declaration uses 'sorry'erdos_593 : answer(sorry) (W : Type) [Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorable := True (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorable All goals completed! 🐙

Erdős Problem 593 — Necessary direction: Every obligatory finite 3-uniform hypergraph is 2-colorable.

This is the natural necessary condition for the conjectural characterization in erdos_593: if a finite 3-uniform hypergraph F is not 2-colorable, one expects to construct a hypergraph with large chromatic number that contains no copy of F.

@[category research open, AMS 5] theorem declaration uses 'sorry'erdos_593.variants.obligatory_implies_two_colorable : answer(sorry) (W : Type) [Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorable := True (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorable All goals completed! 🐙

Erdős Problem 593 — Sufficient direction: Every finite 2-colorable 3-uniform hypergraph is obligatory.

This is the converse direction of the erdos_593 characterization: if 2-colorability matches the graph-case characterization (bipartite ⇔ obligatory), then every 2-colorable finite 3-uniform hypergraph must appear in every 3-uniform hypergraph of chromatic number $> \aleph_0$.

Together with erdos_593.variants.obligatory_implies_two_colorable, this implies erdos_593.

@[category research open, AMS 5] theorem declaration uses 'sorry'erdos_593.variants.two_colorable_implies_obligatory : answer(sorry) (W : Type) [Fintype W] (F : ThreeUniformHypergraph W), F.IsTwoColorable IsObligatory F := True (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), F.IsTwoColorable IsObligatory F All goals completed! 🐙

Conjunction of the two open implications gives the conjectured characterization: if both obligatory_implies_two_colorable and two_colorable_implies_obligatory hold, then the characterization conjectured in erdos_593 (IsObligatory F ↔ F.IsTwoColorable) follows by elementary Iff manipulation.

@[category test, AMS 5] theorem erdos_593.variants.implications_combine (h₁ : (W : Type) [Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorable) (h₂ : (W : Type) [Fintype W] (F : ThreeUniformHypergraph W), F.IsTwoColorable IsObligatory F) : (W : Type) [Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorable := h₁: (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorableh₂: (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), F.IsTwoColorable IsObligatory F (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorable intro W h₁: (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorableh₂: (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), F.IsTwoColorable IsObligatory FW:Typeinst✝:Fintype W (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorable h₁: (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), IsObligatory F F.IsTwoColorableh₂: (W : Type) [inst : Fintype W] (F : ThreeUniformHypergraph W), F.IsTwoColorable IsObligatory FW:Typeinst✝:Fintype WF:ThreeUniformHypergraph WIsObligatory F F.IsTwoColorable All goals completed! 🐙

Graph analogue — bipartite graphs are obligatory (Erdős–Galvin–Hajnal [EGH75]): For the 2-uniform (graph) case, a graph of chromatic cardinal $> \aleph_0$ must contain all finite bipartite graphs. Specifically, for every finite bipartite graph F and every graph G with chromatic cardinal $> \aleph_0$, there is a graph embedding from F into G.

This uses Nonempty (F ↪g G) (graph embedding), aligned with the injective vertex map used in the hypergraph Appears definition.

@[category research solved, AMS 5] theorem declaration uses 'sorry'erdos_593.variants.graph_case_bipartite_obligatory : answer(True) (V : Type*) (G : SimpleGraph V), ℵ₀ < G.chromaticCardinal (W : Type*) [Fintype W] (F : SimpleGraph W), F.IsBipartite Nonempty (F ↪g G) := True (V : Type u_1) (G : SimpleGraph V), ℵ₀ < G.chromaticCardinal (W : Type u_2) [Fintype W] (F : SimpleGraph W), F.IsBipartite Nonempty (F ↪g G) (V : Type u_1) (G : SimpleGraph V), ℵ₀ < G.chromaticCardinal (W : Type u_2) [Fintype W] (F : SimpleGraph W), F.IsBipartite Nonempty (F ↪g G) -- This is the Erdős–Galvin–Hajnal theorem [EGH75]. All goals completed! 🐙

Graph analogue — no odd cycle is obligatory (Erdős–Galvin–Hajnal [EGH75]): For every odd $k \geq 3$, there exists a graph with chromatic cardinal $\aleph_1$ that contains no cycle of length $k$. This shows the class of obligatory graphs is strictly smaller than all finite graphs.

@[category research solved, AMS 5] theorem declaration uses 'sorry'erdos_593.variants.graph_case_no_odd_cycle : answer(True) k : , Odd k 3 k (V : Type*) (G : SimpleGraph V), G.chromaticCardinal = ℵ_ 1 IsEmpty (cycleGraph k →g G) := True (k : ), Odd k 3 k V G, G.chromaticCardinal = ℵ_ 1 IsEmpty (cycleGraph k →g G) (k : ), Odd k 3 k V G, G.chromaticCardinal = ℵ_ 1 IsEmpty (cycleGraph k →g G) -- This is the Erdős–Galvin–Hajnal theorem [EGH75]. All goals completed! 🐙

Vertices must be uncountable: Every 3-uniform hypergraph with chromatic cardinal $> \aleph_0$ must have an uncountable vertex set.

Proof: If V is countable, there exists an injection φ : V → ℕ. Using distinct natural numbers as colors gives a proper coloring, so $\chi(H) \leq #\mathbb{N} = \aleph_0$, contradicting $\chi(H) > \aleph_0$.

@[category textbook, AMS 5] theorem erdos_593.variants.uncountable_vertices_if_large_chromatic {V : Type} (H : ThreeUniformHypergraph V) ( : ℵ₀ < H.chromaticCardinal) : ¬ Countable V := V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinal¬Countable V V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhcount:Countable VFalse -- Since V is countable, there is an injection φ : V → ℕ. V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhcount:Countable Vφ:V :Function.Injective φFalse -- The injection φ is a proper coloring using ℕ as the color type: -- each edge has card 3, so we can extract two distinct vertices with distinct images. have hprop : H.IsProperColoring φ := V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinal¬Countable V intro e V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhcount:Countable Vφ:V :Function.Injective φe:Finset Vhe:e H.edges u e, v e, φ u φ v -- Extract 3 distinct elements from e using H.uniform. V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhcount:Countable Vφ:V :Function.Injective φe:Finset Vhe:e H.edgeshcard:e.card = 3 := H.uniform e he u e, v e, φ u φ v -- Since e.card = 3 ≥ 2, there exist two distinct elements u ≠ v in e. have hge : 1 < e.card := V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinal¬Countable V All goals completed! 🐙 V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhcount:Countable Vφ:V :Function.Injective φe:Finset Vhe:e H.edgeshcard:e.card = 3 := H.uniform e hehge:1 < e.card := Decidable.byContradiction fun a => uncountable_vertices_if_large_chromatic._proof_1 e hcard au:Vhu:u ev:Vhv:v ehuv:u v u e, v e, φ u φ v All goals completed! 🐙 -- So χ(H) ≤ #ℕ = ℵ₀. have hle : H.chromaticCardinal ℵ₀ := V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinal¬Countable V V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhcount:Countable Vφ:V :Function.Injective φhprop:H.IsProperColoring φ := fun e he => have hcard := H.uniform e he; have hge := Decidable.byContradiction fun a => uncountable_vertices_if_large_chromatic._proof_1 e hcard a; Exists.casesOn (Finset.one_lt_card.mp hge) fun u h => And.casesOn h fun hu right => Exists.casesOn right fun v h => And.casesOn h fun hv huv => Exists.intro u hu, Exists.intro v hv, fun heq => huv ( heq)BddBelow {κ | C, #C = κ f, H.IsProperColoring f}V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhcount:Countable Vφ:V :Function.Injective φhprop:H.IsProperColoring φ := fun e he => have hcard := H.uniform e he; have hge := Decidable.byContradiction fun a => uncountable_vertices_if_large_chromatic._proof_1 e hcard a; Exists.casesOn (Finset.one_lt_card.mp hge) fun u h => And.casesOn h fun hu right => Exists.casesOn right fun v h => And.casesOn h fun hv huv => Exists.intro u hu, Exists.intro v hv, fun heq => huv ( heq)ℵ₀ {κ | C, #C = κ f, H.IsProperColoring f} V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhcount:Countable Vφ:V :Function.Injective φhprop:H.IsProperColoring φ := fun e he => have hcard := H.uniform e he; have hge := Decidable.byContradiction fun a => uncountable_vertices_if_large_chromatic._proof_1 e hcard a; Exists.casesOn (Finset.one_lt_card.mp hge) fun u h => And.casesOn h fun hu right => Exists.casesOn right fun v h => And.casesOn h fun hv huv => Exists.intro u hu, Exists.intro v hv, fun heq => huv ( heq)BddBelow {κ | C, #C = κ f, H.IsProperColoring f} -- The set {κ | ∃ C, #C = κ ∧ ∃ f, proper} is bounded below by 0. All goals completed! 🐙 V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhcount:Countable Vφ:V :Function.Injective φhprop:H.IsProperColoring φ := fun e he => have hcard := H.uniform e he; have hge := Decidable.byContradiction fun a => uncountable_vertices_if_large_chromatic._proof_1 e hcard a; Exists.casesOn (Finset.one_lt_card.mp hge) fun u h => And.casesOn h fun hu right => Exists.casesOn right fun v h => And.casesOn h fun hv huv => Exists.intro u hu, Exists.intro v hv, fun heq => huv ( heq)ℵ₀ {κ | C, #C = κ f, H.IsProperColoring f} All goals completed! 🐙 All goals completed! 🐙

No hyperedges implies chromatic cardinal ≤ 1: A 3-uniform hypergraph with no edges can be properly colored with a single color, so its chromatic cardinal is at most 1. In particular, $\chi(H) > \aleph_0$ implies H has at least one hyperedge.

@[category textbook, AMS 5] theorem erdos_593.variants.nonempty_edges_if_large_chromatic {V : Type} (H : ThreeUniformHypergraph V) ( : ℵ₀ < H.chromaticCardinal) : H.edges.Nonempty := V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalH.edges.Nonempty V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:¬H.edges.NonemptyFalse V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:H.edges = False -- H has no edges (hempty : H.edges = ∅), so any coloring is proper. have hprop : H.IsProperColoring (fun _ : V => (0 : Fin 1)) := V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalH.edges.Nonempty intro e V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:H.edges = e:Finset Vhe:e H.edges u e, v e, (fun x => 0) u (fun x => 0) v V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:H.edges = e:Finset Vhe:e u e, v e, (fun x => 0) u (fun x => 0) v All goals completed! 🐙 -- Hence χ(H) ≤ 1 < ℵ₀. have hle : H.chromaticCardinal 1 := V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalH.edges.Nonempty V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:H.edges = hprop:H.IsProperColoring fun x => 0 := fun e he => False.elim ((mem_empty_iff_false e).mp (Eq.mp (congrArg (fun _a => e _a) hempty) he))BddBelow {κ | C, #C = κ f, H.IsProperColoring f}V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:H.edges = hprop:H.IsProperColoring fun x => 0 := fun e he => False.elim ((mem_empty_iff_false e).mp (Eq.mp (congrArg (fun _a => e _a) hempty) he))1 {κ | C, #C = κ f, H.IsProperColoring f} V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:H.edges = hprop:H.IsProperColoring fun x => 0 := fun e he => False.elim ((mem_empty_iff_false e).mp (Eq.mp (congrArg (fun _a => e _a) hempty) he))BddBelow {κ | C, #C = κ f, H.IsProperColoring f} All goals completed! 🐙 V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:H.edges = hprop:H.IsProperColoring fun x => 0 := fun e he => False.elim ((mem_empty_iff_false e).mp (Eq.mp (congrArg (fun _a => e _a) hempty) he))1 {κ | C, #C = κ f, H.IsProperColoring f} V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:H.edges = hprop:H.IsProperColoring fun x => 0 := fun e he => False.elim ((mem_empty_iff_false e).mp (Eq.mp (congrArg (fun _a => e _a) hempty) he))#(Fin 1) = 1 All goals completed! 🐙 V:TypeH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalhempty:H.edges = hprop:H.IsProperColoring fun x => 0 := fun e he => False.elim ((mem_empty_iff_false e).mp (Eq.mp (congrArg (fun _a => e _a) hempty) he))hle:H.chromaticCardinal 1 := csInf_le (Exists.intro 0 fun x x_1 => match x_1 with | Exists.intro w left, Exists.intro w_1 h => Cardinal.zero_le x) (Exists.intro (Fin 1) of_eq_true (Eq.trans (congrArg (fun x => x = 1) (Eq.trans (mk_fintype (Fin 1)) (Eq.trans (congrArg Nat.cast Fintype.card_unique) Nat.cast_one))) (eq_self 1)), Exists.intro (fun x => 0) hprop)h1le:1 ℵ₀ := le_of_lt one_lt_aleph0False All goals completed! 🐙

Monotonicity of the obligatory property: If F₁ appears in F₂ and F₂ is obligatory, then F₁ is also obligatory.

Proof: For any H with $\chi(H) > \aleph_0$, since F₂ is obligatory, F₂ appears in H via some injection φ₂. Since F₁ appears in F₂ via φ₁, the composition φ₂ ∘ φ₁ witnesses that F₁ appears in H.

@[category textbook, AMS 5] theorem erdos_593.variants.obligatory_monotone {W₁ W₂ : Type} [Fintype W₁] [Fintype W₂] [DecidableEq W₂] {F₁ : ThreeUniformHypergraph W₁} {F₂ : ThreeUniformHypergraph W₂} (h12 : F₁.Appears F₂) (hObl : IsObligatory F₂) : IsObligatory F₁ := W₁:TypeW₂:Typeinst✝²:Fintype W₁inst✝¹:Fintype W₂inst✝:DecidableEq W₂F₁:ThreeUniformHypergraph W₁F₂:ThreeUniformHypergraph W₂h12:F₁.Appears F₂hObl:IsObligatory F₂IsObligatory F₁ intro V W₁:TypeW₂:Typeinst✝²:Fintype W₁inst✝¹:Fintype W₂inst✝:DecidableEq W₂F₁:ThreeUniformHypergraph W₁F₂:ThreeUniformHypergraph W₂h12:F₁.Appears F₂hObl:IsObligatory F₂V:Type_hV:DecidableEq V (H : ThreeUniformHypergraph V), ℵ₀ < H.chromaticCardinal F₁.Appears H W₁:TypeW₂:Typeinst✝²:Fintype W₁inst✝¹:Fintype W₂inst✝:DecidableEq W₂F₁:ThreeUniformHypergraph W₁F₂:ThreeUniformHypergraph W₂h12:F₁.Appears F₂hObl:IsObligatory F₂V:Type_hV:DecidableEq VH:ThreeUniformHypergraph Vℵ₀ < H.chromaticCardinal F₁.Appears H W₁:TypeW₂:Typeinst✝²:Fintype W₁inst✝¹:Fintype W₂inst✝:DecidableEq W₂F₁:ThreeUniformHypergraph W₁F₂:ThreeUniformHypergraph W₂h12:F₁.Appears F₂hObl:IsObligatory F₂V:Type_hV:DecidableEq VH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalF₁.Appears H W₁:TypeW₂:Typeinst✝²:Fintype W₁inst✝¹:Fintype W₂inst✝:DecidableEq W₂F₁:ThreeUniformHypergraph W₁F₂:ThreeUniformHypergraph W₂h12:F₁.Appears F₂hObl:IsObligatory F₂V:Type_hV:DecidableEq VH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalφ₂:W₂ Vhφ₂_inj:Function.Injective φ₂hφ₂_edge: e F₂.edges, Finset.image φ₂ e H.edgesF₁.Appears H W₁:TypeW₂:Typeinst✝²:Fintype W₁inst✝¹:Fintype W₂inst✝:DecidableEq W₂F₁:ThreeUniformHypergraph W₁F₂:ThreeUniformHypergraph W₂hObl:IsObligatory F₂V:Type_hV:DecidableEq VH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalφ₂:W₂ Vhφ₂_inj:Function.Injective φ₂hφ₂_edge: e F₂.edges, Finset.image φ₂ e H.edgesφ₁:W₁ W₂hφ₁_inj:Function.Injective φ₁hφ₁_edge: e F₁.edges, Finset.image φ₁ e F₂.edgesF₁.Appears H W₁:TypeW₂:Typeinst✝²:Fintype W₁inst✝¹:Fintype W₂inst✝:DecidableEq W₂F₁:ThreeUniformHypergraph W₁F₂:ThreeUniformHypergraph W₂hObl:IsObligatory F₂V:Type_hV:DecidableEq VH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalφ₂:W₂ Vhφ₂_inj:Function.Injective φ₂hφ₂_edge: e F₂.edges, Finset.image φ₂ e H.edgesφ₁:W₁ W₂hφ₁_inj:Function.Injective φ₁hφ₁_edge: e F₁.edges, Finset.image φ₁ e F₂.edgese:Finset W₁he:e F₁.edgesFinset.image (φ₂ φ₁) e H.edges -- e.image (φ₂ ∘ φ₁) = (e.image φ₁).image φ₂ by Finset.image_image have heq : e.image (φ₂ φ₁) = (e.image φ₁).image φ₂ := W₁:TypeW₂:Typeinst✝²:Fintype W₁inst✝¹:Fintype W₂inst✝:DecidableEq W₂F₁:ThreeUniformHypergraph W₁F₂:ThreeUniformHypergraph W₂h12:F₁.Appears F₂hObl:IsObligatory F₂IsObligatory F₁ All goals completed! 🐙 W₁:TypeW₂:Typeinst✝²:Fintype W₁inst✝¹:Fintype W₂inst✝:DecidableEq W₂F₁:ThreeUniformHypergraph W₁F₂:ThreeUniformHypergraph W₂hObl:IsObligatory F₂V:Type_hV:DecidableEq VH:ThreeUniformHypergraph V:ℵ₀ < H.chromaticCardinalφ₂:W₂ Vhφ₂_inj:Function.Injective φ₂hφ₂_edge: e F₂.edges, Finset.image φ₂ e H.edgesφ₁:W₁ W₂hφ₁_inj:Function.Injective φ₁hφ₁_edge: e F₁.edges, Finset.image φ₁ e F₂.edgese:Finset W₁he:e F₁.edgesheq:Finset.image (φ₂ φ₁) e = Finset.image φ₂ (Finset.image φ₁ e) := Eq.mpr (id (congrArg (fun _a => Finset.image (φ₂ φ₁) e = _a) Finset.image_image)) (Eq.refl (Finset.image (φ₂ φ₁) e))Finset.image φ₂ (Finset.image φ₁ e) H.edges All goals completed! 🐙

The empty hypergraph is trivially obligatory: The 3-uniform hypergraph on PEmpty (no vertices, no edges) appears in every hypergraph via the empty injection.

This degenerate case confirms the definition is well-formed.

@[category textbook, AMS 5] theorem erdos_593.variants.empty_hypergraph_obligatory : IsObligatory (W := PEmpty) , fun _ h => (Set.mem_empty_iff_false _).mp h |>.elim := IsObligatory { edges := , uniform := } intro V V:Type_hV:DecidableEq V (H : ThreeUniformHypergraph V), ℵ₀ < H.chromaticCardinal { edges := , uniform := }.Appears H V:Type_hV:DecidableEq VH:ThreeUniformHypergraph Vℵ₀ < H.chromaticCardinal { edges := , uniform := }.Appears H V:Type_hV:DecidableEq VH:ThreeUniformHypergraph V_hχ:ℵ₀ < H.chromaticCardinal{ edges := , uniform := }.Appears H All goals completed! 🐙 end Erdos593