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Erdős Problem 647

Reference: erdosproblems.com/647

namespace Erdos647 open Filter ArithmeticFunction.sigma

Let $\tau(n)$ count the number of divisors of $n$. Is there some $n > 24$ such that $$ \max_{m < n}(m + \tau(m)) \leq n + 2? $$

@[category research open, AMS 11] theorem declaration uses 'sorry'erdos_647 : answer(sorry) n > 24, m : Fin n, m + σ 0 m n + 2 := True n > 24, m, m + (σ 0) m n + 2 All goals completed! 🐙

This is true for $n = 24$.

@[category research solved, AMS 11] theorem erdos_647.variants.twenty_four : m : Fin 24, (m : ) + σ 0 m 26 := m, m + (σ 0) m 26 exact ciSup_le <| (x : Fin 24), x + (σ 0) x 26 All goals completed! 🐙

Erdős says 'it is extremely doubtful' that there are infinitely many such $n$, and in fact suggests that $$ lim_{n\to\infty} \max_{m < n}(\tau(m) + m − n) = \infty. $$

@[category research open, AMS 11] theorem declaration uses 'sorry'erdos_647.variants.lim : answer(sorry) atTop.Tendsto (fun n m : Fin n, σ 0 m + m - n) atTop := True Tendsto (fun n => m, (σ 0) m + m - n) atTop atTop All goals completed! 🐙

Erdős says it 'seems certain' that for every $k$ there are infinitely many $n$ for which $$ \max_{n−k < m < n}(m + \tau(m)) ≤ n + 2. $$

@[category research open, AMS 11] theorem declaration uses 'sorry'erdos_647.variants.infinite : answer(sorry) k, { n | m : Set.Ioo (n - k) n, m + σ 0 m n + 2 }.Infinite := True (k : ), {n | m, m + (σ 0) m n + 2}.Infinite All goals completed! 🐙 end Erdos647