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Erdős Problem 92
Both questions here are disproved, by way of Erdős Problem 90. The source says so directly: this
is a stronger form of the unit distance conjecture, so the disproof of that conjecture disproves
these too. See FormalConjectures.ErdosProblems.«90».
For a given point x and a set of other points, this function finds the maximum number of points
that lie on a single circle centered at x. It does this by grouping the other points by their
distance to x and finding the size of the largest group.
The set of all possible values k for which there exists a set of n points
satisfying the hasMinEquidistantProperty k. The function f(n) will be the supremum of this set.
A sanity check to ensure the set of possible f(n) values is bounded above. A trivial bound is
n, since the points equidistant from any x form a subset of the other n - 1 points.
This ensures sSup is well-defined.
Let $f(n)$ be maximal such that there exists a set $A$ of $n$ points in $\mathbb^2$
in which every $x \in A$ has at least $f(n)$ points in $A$ equidistant from $x$.
The source records this as disproved: "This is a stronger form of the unit distance conjecture
(see [90]). As such the recent disproof of [90] also disproves this." That disproof is
Erdos90.erdos_90, which this repository already records as research solved with the answer
False.
Or even $f(n) < n^{c/\log\log n}$ for some constant $c > 0$?
Also disproved, and by the weak form rather than separately: since $c/\log\log n \to 0$, the bound
$n^{c/\log\log n}$ is of the form $n^{o(1)}$, so this statement implies
erdos_92.variants.weak and is false whenever that one is.
@[categoryresearchsolved,AMS52]theoremerdos_92.variants.strong:answer(False)↔∃c>0,∀ᶠninatTop,(fn:ℝ)≤n^(c/(n:ℝ).log.log):=by⊢ False↔∃c>0,∀ᶠ(n:ℕ)inatTop,↑(fn)≤↑n^(c/Real.log(Real.log↑n))sorryAll goals completed! 🐙-- TODO(firsching): formalize the rest of the remarksendErdos92