/- Copyright 2026 The Formal Conjectures Authors. Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except in compliance with the License. You may obtain a copy of the License at https://www.apache.org/licenses/LICENSE-2.0 Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the specific language governing permissions and limitations under the License. -/ import FormalConjecturesUtil

Number of primes $< n^2$

Number of primes strictly less than $n^2$.

References:

namespace OeisA38107

Number of primes strictly less than $n^2$.

def a (n : ) : := (Nat.primesBelow (n ^ 2)).card

Value of the sequence a at 0.

@[category test, AMS 11] theorem a_0 : a 0 = 0 := a 0 = 0 All goals completed! 🐙

Value of the sequence a at 1.

@[category test, AMS 11] theorem a_1 : a 1 = 0 := a 1 = 0 All goals completed! 🐙

Value of the sequence a at 2.

@[category test, AMS 11] theorem a_2 : a 2 = 2 := a 2 = 2 All goals completed! 🐙

Value of the sequence a at 3.

@[category test, AMS 11] theorem a_3 : a 3 = 4 := a 3 = 4 All goals completed! 🐙

Value of the sequence a at 4.

@[category test, AMS 11] theorem a_4 : a 4 = 6 := a 4 = 6 All goals completed! 🐙

Value of the sequence a at 5.

@[category test, AMS 11] theorem a_5 : a 5 = 9 := a 5 = 9 All goals completed! 🐙

Conjecture: all the numbers $\sum_{i=j}^k \frac{1}{a(i)}$ with $1 < j \le k$ have pairwise distinct fractional parts.

    Zhi-Wei Sun, Sep 24 2015

@[category research open, AMS 11] theorem conjecture (j k j' k' : ) (hj : 1 < j) (hjk : j k) (hj' : 1 < j') (hj'k' : j' k') (h_eq : Int.fract ( i Finset.Icc j k, (1 : ) / (a i : )) = Int.fract ( i Finset.Icc j' k', (1 : ) / (a i : ))) : j = j' k = k' := j:k:j':k':hj:1 < jhjk:j khj':1 < j'hj'k':j' k'h_eq:Int.fract (∑ i Finset.Icc j k, 1 / (a i)) = Int.fract (∑ i Finset.Icc j' k', 1 / (a i))j = j' k = k' All goals completed! 🐙end OeisA38107