/- Copyright 2026 The Formal Conjectures Authors. Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except in compliance with the License. You may obtain a copy of the License at https://www.apache.org/licenses/LICENSE-2.0 Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the specific language governing permissions and limitations under the License. -/ module public import Mathlib.Data.Int.Order.Basic public import Mathlib.Data.Nat.Basic public import Mathlib.Data.Nat.Init

A discrete intermediate value theorem

An integer-valued sequence whose consecutive terms differ by at most 1 attains every integer value lying between two of its terms. This is the discrete analogue of the intermediate value theorem for a unit-step walk on .

@[expose] public section

Discrete intermediate value theorem. If an integer-valued sequence f : ℕ → ℤ has consecutive terms differing by at most 1, then it attains every value between f a and f b: for a ≤ b and f a ≤ t ≤ f b there is some index c ∈ [a, b] with f c = t.

theorem Int.exists_eq_of_natAbs_sub_le_one (f : ) (hf : n, (f (n + 1) - f n).natAbs 1) {a b : } (hab : a b) {t : } (hta : f a t) (htb : t f b) : c, a c c b f c = t := f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b:hab:a bt:hta:f a thtb:t f b c, a c c b f c = t induction b, hab using Nat.le_induction with f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b:t:hta:f a thtb:t f a c, a c c a f c = t All goals completed! 🐙 f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1) c, a c c b + 1 f c = t f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1)h:t f b c, a c c b + 1 f c = tf: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1)h:¬t f b c, a c c b + 1 f c = t f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1)h:t f b c, a c c b + 1 f c = t f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1)h:t f bc:hac:a chcb:c bhfc:f c = t c, a c c b + 1 f c = t exact c, hac, f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1)h:t f bc:hac:a chcb:c bhfc:f c = tc b + 1 All goals completed! 🐙, hfc f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1)h:¬t f b c, a c c b + 1 f c = t f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1)h:¬t f bhstep:(f (b + 1) - f b).natAbs 1 c, a c c b + 1 f c = t exact b + 1, f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1)h:¬t f bhstep:(f (b + 1) - f b).natAbs 1a b + 1 All goals completed! 🐙, le_refl _, f: hf: (n : ), (f (n + 1) - f n).natAbs 1a:b✝:t:hta:f a tb:hb:a bih:t f b c, a c c b f c = thtb:t f (b + 1)h:¬t f bhstep:(f (b + 1) - f b).natAbs 1f (b + 1) = t All goals completed! 🐙