9 Four times \(π^2/6\)
\[ \sum _{n\ge 1}\frac{1}{n^2} = \frac{\pi ^2}{6} \]
TODO
\[ \sum _{k\ge 0}\frac{1}{(2 * k + 1)^2} = \frac{\pi ^2}{8} \]
TODO
\[ \sum _{n\ge 1}\frac{1}{n^2} = \frac{\pi ^2}{6} \]
TODO
\[ \sum _{n\ge 1}\frac{1}{n^2} = \frac{\pi ^2}{6} \]
TODO
Collecting the proofs from the chapter